16=1/2(43+b^2)

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Solution for 16=1/2(43+b^2) equation: 



16=1/2(43+b^2)

We move all terms to the left:

16-(1/2(43+b^2))=0



Domain of the equation: 2(43+b^2))!=0

b∈R



We multiply all the terms by the denominator


-(1+16*2(43+b^2))=0



We calculate terms in parentheses: -(1+16*2(43+b^2)), so:

1+16*2(43+b^2)

determiningTheFunctionDomain
16*2(43+b^2)+1

Wy multiply elements

32b(4+1

Back to the equation:

-(32b(4+1)



We add all the numbers together, and all the variables

-(32b5=0

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